Question

24. Certain force acting on a 20kg of mass changes its velocity from 5ms to
2ms- Calculate the work done by the force.
9 X 3 = 27​

Answer 1

Answer:

Explanation:

m = 20kg

u = 5m/s

v = 2m/s

w = 1/2 mv^2 - 1/2 mu^2

= 1/2 m [ v^2 -u^2]

=1/2 * 20 [ 5^2 - 2^2]

= 10 * [ 25-4]

= 10 * 21

= 210 J