24. Correct increasing order of osmotic pressure for the following is
(1) Sucrose(0.1 M) < glucose(0.5 M) < urea(1M) < NaCl(2M)
(2) Glucose(0.5 M) < urea(1M) < NaCl(2M) < Sucrose(0.1 M)
(3) Urea(1M) < NaCl(2M) < glucose(0.5 M) < Sucrose(0.1 M)
(4) NaCl(2M) < sucrose(0.1 M) < glucose(0.5 M) < urea(1M)
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Answered by
126
ANSWER:
- Increasing order of osmotic pressure is Sucrose(0.1 M) < Glucose(0.5 M) < Urea(1 M) < NaCl(2 M)
GIVEN:
- 0.1 M Sucrose.
- 0.5 M Glucose.
- 1 M Urea.
- 2 M NaCl.
TO FIND:
- Increasing order of osmotic pressure.
EXPLANATION:
Sucrose:
- i = 1
- C = 0.1 M
→ π = 1(0.1)RT
→ π = 0.1 × RT
Glucose:
- i = 1
- C = 0.5 M
→ π = 1(0.5)RT
→ π = 0.5 × RT
Urea:
- i = 1
- C = 1 M
→ π = 1(1)RT
→ π = RT
NaCl:
- i = 2
- C = 2 M
→ π = 2(2)RT
→ π = 4RT
Correct increasing order of osmotic pressure is Sucrose(0.1 M) < glucose(0.5 M) < urea(1M) < NaCl(2M)
Answered by
89
Given that , 0.1 M ( Mole ) of Sucrose , 0.5 M ( Mole ) of Gulucose , 1 M ( Mole ) of Urea & 2 M of NaCl .
Need To Find : Increasing order of osmotic pressure ?
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
As , We know that ,
⠀⠀⠀⠀▪︎⠀Formula for OSMOTIC PRESSURE :
⠀⠀⠀⠀⠀Where,
- π is the Osmotic Pressure .
- i is Vant's off index .
- C is molar concentration of solute in solution .
- R is the Universal gas constant .
- T is the Temperature in Kelvin .
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
- i or Vant's off index of Sucrose is 1 &
- C or molar Concentration of Sucrose is 0.1 M ( Mole ) .
- Osmotic Pressure of 0.1 M of Sucrose is 0.1 RT .
- i or Vant's off index of Gulucose is 1 &
- C or molar Concentration of Gulucose is 0.5 M ( Mole ) .
- Osmotic Pressure of 0.5 M of Gulucose is 0.5 RT .
- i or Vant's off index of Gulucose is 1 &
- C or molar Concentration of Gulucose is 1 M ( Mole ) .
- Osmotic Pressure of 1 M of Urea is 1 RT .
- i or Vant's off index of Gulucose is 2 &
- C or molar Concentration of Gulucose is 2 M ( Mole ) .
- Osmotic Pressure of 2 M of NaCl is 2 RT .
Therefore,
⠀⠀⠀⠀⠀⠀⠀▪︎⠀⠀Increasing Order of Osmotic pressure will be :
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