Question

24. Find a if 2x - 3 is a factor of 6x³ - x² - 10x + a. Find a

Answer 1

Answer:

First of all we have to find the zero of the divisor

so zero of divisor is

2x - 3 = 0

=> 2x = 3

=> x = 3/2

If (2x - 3) is a factor of (6x³ - x² - 10x + a) then by remainder theorem, remainder will be zero.

=> Putting the value of x we get

6(3/2)³ - (3/2)² - 10(3/2) + a = 0

=> 81/4 - 9/4 - 15 +a = 0

=> 81/4 - 9/4 - 60/4 + a = 0

=> 12/4 + a = 0

=> 3 + a = 0

=> a= (-3)

Step-by-step explanation:

Answer 2

Answer:

The ans. is a = -3

Step-by-step explanation:

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