Math, asked by anandmaurya2024, 7 months ago

24)Find the 31st term of an AP whose lith term is 38 and the 16th term is
73.​

Answers

Answered by nimmalabhaskargoud
0

ANSWER

Given that, a

11

=38 a

16

=73

We know that,

a

n

=a+(n−1)d

a

11

=a+(11−1)d

38=a+10d ... (i)

Similarly,

a

16

=a+(16−1)d

73=a+15d ... (ii)

On subtracting (i) from (ii), we get

35=5d

∴d=7

From equation (i),

38=a+(10)(7)

⇒38−70=a

∴a=−32

Now a

31

=a+(31−1)d

=−32+30(7)

=−32+210

=178

Hence, 31

st

term is 178.

hope it helps

Answered by jhontron45
0

Answer:

108

Step-by-step explanation:

a=38

a₁₆=a+15d

⇒73=38+15d

⇒35=15d

⇒d=35÷15

⇒d=7/3

a₃₁=a+30d

⇒a₃₁=38+30*7/3

⇒a₃₁=38+70

⇒a₃₁=108

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