Question

24. find the area of a regular hexagon of side 8cm and perpendicular to side 4.5cm.
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Answer 1

Given that side of a hexagon = a=8 cm

We know that the area of the regular hexagon

$\frac{3 \sqrt{3} }{2} {a}^{2}$

$\frac{3 \sqrt{3} }{2} \times {8}^{2}$

$\frac{3 \sqrt{3} }{2} \times 64$

$= 96 \sqrt{3} \: \: \: {cm}^{2}$

∴ Area of regular hexagon =

$= 96 \sqrt{3} \: \: \: {cm}^{2}$

Answer 2

Answer:

Area of a regular hexagon = 166.28 sq cm

Step-by-step explanation:

Given

Side of a regular hexagon = 8 cm

Perpendicular side = 4 . 5cm

Area of a Regular Hexagon = 3√3 a2 / 2

A = 3√3 ( 8×8 ) / 2

A = 3√3 ( 64 ) / 2

A = 166.28 sq cm