Math, asked by Clarahelps, 4 months ago

24.Find the compound interest for Rs. 40,000 at 10% compounded annually for

3 years and compare it with simple interest obtained for the same principal,

period and at the same rate of interest. ​

Answers

Answered by pushpadevihot
1

Simple Interest I=

100

PNR

Here for first year,

P=Rs40,000

N=1year

R=10 %

So, Interest at the end of 1st year I=

100

40,000×1×10

=Rs4,000

And for second year,

P=Rs40,000+Rs4,000=Rs44,000

N=1year

R=10 %

I=

100

44,000×1×10

=Rs4,400

Answered by prema0anand
5

Answer:

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Step-by-step explanation:

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