Question

***24. Find the equations of the straight lines passing through the point (-3, 2) and making
an angle of 45° with the straight line 3x – y +4=0.
​

Answer 1

Answer:

yujfuuzjsjfmcmrmfjfkfm

Answer 2

Step-by-step explanation:

Let slope of required line be m

1

y=3x+4 is of form y=mx+c and has slope m

2

=3

⇒tan45=

∣

∣

∣

∣

∣

1+m

1

m

2

m

2

−m

1

∣

∣

∣

∣

∣

=

1+3m

30m

1

=1

⇒3−m

1

=1+3m,

or $3-m_1=-1-3m_1$$$

⇒4m

1

=2⇒m

1

=

2

1

or 2m

1

=−4

⇒m

1

=−2

⇒ Equations of straight lines

y−2=

2

1

(x+3) or y−2=−2(x+5)

⇒2y−4=x+3 ⇒y−2=−2x−6

⇒2y=x+7 y=−2x−4.