24. Find the factors of the given 1 point
polynomial
2ycube + y2 – 2y-1
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Answer:
(y-1) (y+1) (2y+1) this is the answer
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Step-by-step explanation:
p(1) = 2(1)³+1²-2(1)-1
= 2+1-2-1
= 0
By Factor theorem,
(y-1) is a factor of p(y).
2y³+y²-2y-1
=2y²(y-1)+3y(y-1)+1(y-1)
=(y-1)(2y²+3y+1)
=(y-1)(2y²+2y+1y+1)
=(y-1)[2y(y+1)+1(y+1)]
=(y-1)(y+1)(2y+1)
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