Question

24. Find the value of p and q, if x2 - 4 is a factor of px4 + 2x - 3x + x - 4.​

Answer 1

Step-by-step explanation:

x= -4/2 = -2

p(-2) = 2(-2) -3(-2) +(-2)-4

= (-4)+6+8

= -4 +14

= 10

Answer 2

Step-by-step explanation:

x2 -4 is the factor

x2- 2 square

x-2 and x+2 are factors

2 and-2 are zeroes

put x=2 in p(x)=0

p(2)4+2×2- 3×2+2-4=0

16p+4-6-4=0

16p-6 =0

p=6/16

p=3/8

put x=-2

p(-2)4+2×(-2)-3×(-2)+(-2)-4=0

16p-4+6-2-4=0

16p -4=0

p=4/16

p=1/4

this value of p are3/8 and1/4

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