Math, asked by krishniranjan21, 1 month ago

24. Find the value(s) of k so that the pair of equations 2x + 3y = 4 and (k + 2)x + 6y = 3k + 2 have infinitely
many solutions.

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Answers

Answered by sanadas941
2

Answer:

2x + 3y = 4 Read more on Sarthaks.com - https://www.sarthaks.com/173761/for-what-value-of-k-2x-3y-4-and-k-2-x-6y-3k-2-will-have-infinitely-many-solutions

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