Question

24. Four identical resistors each of R = 4 ohm are joined in a circuit as shown. The cell B has emf of 2 volt
and its internal resistance is negligible. Find out current read by ammeter A.
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Answer 1

Answer:

2A is the reading of ammeter in the circuit.

Explanation:

I=4V/4R

I=4*2/4

I= 8/4=2A

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Answer 2

Thus the ammeter A will read 2 Ampere amount of current.

Explanation:

The potential difference will be the same for all the resistors so the effective resistance would be =R/4 (Parallel circuit)

By Ohm's Law,

V=IR

=>2=I x R/4

=>I=8/R    Ampere

R=4 ohms , so I=8/R=2 Ampere

So the ammeter will show 8/R = 2 Ampere