Question

24), Four times the difference in ages of C and A is one more then the age of B. percentage of A's age to C's age is 75%. if the ratio of B's age 5 years hence to C's age age 1 year ago is 4:3. Find the average of ages A and C.

a) 20 (b) 19 (C) 12 (d) 14 (e) None​

Answer 1

Answer:

14  

Step-by-step explanation:

A is 12, B is 15, C is 16

(12 + 16) / 2 = 14  

Answer 2

Given :    Four times the difference in ages of C and A is one more then the age of B. percentage of A's age to C's age is 75%. if the ratio of B's age 5 years hence to C's age age 1 year ago is 4:3

To find : the average of ages A and C.

Solution:

Let say Age of  A , B & C  are  A , B & C

4(C - A)  = B + 1

=>4C  - 4A  = B + 1

A age = (75/100)C  

=> 3C  = 4A

putting in above

=> 4C - 3C = B + 1

=> C  = B + 1

=> C - 1 = B

(B + 5) / (C - 1)   =  4/3

=> (B + 5) /B  =  4/3

=> 3B + 15  = 4B

=>B = 15

=> C = 16

3C  = 4A => A = 12

Average age of A & C  =  (12 + 16)/2 = 14 Years

Average age of A & C  = 14 Years

option D is correct

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