(24) from the top of a clift 20m high, the angle
of elevation of a tower is forend to be equal
to the angle of depression of the foot of the
tower. Find the height of the lower. 240m
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let the height of the tower be x metres and the base distance or distance between foot be y metres
let the angle be A
in ∆ABC
tanA = AB/BC = 20/y
tanA = 20/y
in ∆ADE
tanA = DE/AE = (x-20)/y
tanA = (x-20)/y
Since, both the angles are equal
20/y = (x-20)/y
20 = x - 20
x = 40m
therefore height of tower is 40 metres
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