24 gr of H2 diffuses in 5 sec ,find out mass of O2 diffused in 10sec?
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Answer:
Time taken for oxygen diffusion=10 sec
Also pressure,volume,temperature is constant.
Molar mass of oxygen=32g/mole
Molar mass of sulphur dioxide=64g/mole
According to graham's law of diffusion/effusion
r∝
M
1
r=rate of diffusion
M=molar mass
r
SO
2
r
O
2
=
M
O
2
M
SO
2
since,
r=V/T,r∝
t
1
t
O
2
t
SO
2
=
M
O
2
M
SO
2
10
t
SO
2
=
32
64
t
SO
2
=14.14
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