Question

24 gr of H2 diffuses in 5 sec ,find out mass of O2 diffused in 10sec?
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Answer 1

Answer:

Time taken for oxygen diffusion=10 sec

Also pressure,volume,temperature is constant.

Molar mass  of oxygen=32g/mole

Molar mass of sulphur dioxide=64g/mole

According to graham's law of diffusion/effusion

r∝  

M

1

​

 

​

     

 r=rate of diffusion

 M=molar mass

r  

SO  

2

​

 

​

 

r  

O  

2

​

 

​

 

​

=  

M  

O  

2

​

 

​

 

M  

SO  

2

​

 

​

 

​

 

​

 

since,

r=V/T,r∝  

t

1

​

 

t  

O  

2

​

 

​

 

t  

SO  

2

​

 

​

 

​

=  

M  

O  

2

​

 

​

 

M  

SO  

2

​

 

​

 

​

 

​

 

10

t  

SO  

2

​

 

​

 

​

=  

32

64

​

 

​

 

t  

SO  

2

​

 

​

=14.14