Math, asked by birajdutta364, 5 months ago

(24) How many metal sheets of size Im * lm will be required to form a
cylinder of height 14 m. and radius of the base 2 m?​

Answers

Answered by ItzNila
8

Step-by-step explanation:

GIVEN:-

=> Dimensions = 1m × 1m

TO FIND:-

=> The total number of metal sheets required to form a cylinder.

UNDERSTANDING THE CONCEPT:-

=> According to the question,

we have radius as 2m and height as 14m with dimension 1m × 1m.

From this we can find the total number of metal sheets required to form a cylinder by using respective formula.

CONCEPT REFRESHER:-

=> No. of metal sheets = surface area of cylinder ÷ Area of each metal sheet.

REQUIRED ANSWER:-

✓Let's do it!!

 =  >  \frac{2 \times 3.14 \times  \times 14 +2 \times 3.14 \times 2 {}^{2}  }{1 {}^{2} }

 =  > 175.84 + 25.12

 =  > 200.96

We can keep as such as 200. 96 or round it of to 201

Therefore, the total number of metal sheets required to form a cylinder is 201

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