Chemistry, asked by sanjaygc2004, 2 months ago

24. i) Explain softening of permanent hardness of water by Calgon's process.
ii) Give an example of ionic hydride.

Answers

Answered by viditshetty290
0

Answer:

Calgon is a trade name of a complex salt, sodium hexametaphosphate, (NaPO

3

)

6

. It is used for softening hard water. Calgon ionizes to give a complex anion:

(NaPO

3

)

6

or Na

2

(Na

4

P

6

O

18

)→2Na

+

+Na

4

P

6

O

18

2−

The addition of Calgon to hard water causes the calcium and magnesium ions of hard water to displace sodium ions from the anion of Calgon.

Ca

2+

+Na

4

P

6

O

18

2−

→2Na

+

+CaNa

2

P

6

O

18

2−

This results in the removal of calcium and magnesium ions from hard water in the form of a complex with Calgon. The water is softened and sodium ions are released into water.

Answered by Anonymous
0

Answer:

Calgon is a trade name of a complex salt, sodium hexametaphosphate, (NaPO  

3

)  

6

. It is used for softening hard water. Calgon ionizes to give a complex anion:

(NaPO  

3

)  

6

 or Na  

2

(Na  

4

P  

6

O  

18

)→2Na  

+

+Na  

4

P  

6

O  

18

2−

 

The addition of Calgon to hard water causes the calcium and magnesium ions of hard water to displace sodium ions from the anion of Calgon.

Ca  

2+

+Na  

4

P  

6

O  

18

2−

→2Na  

+

+CaNa  

2

P  

6

O  

18

2−

 

This results in the removal of calcium and magnesium ions from hard water in the form of a complex with Calgon. The water is softened and sodium ions are released into water.

Explanation:

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