Math, asked by seemaabhi22, 11 months ago

24. If 2 sin x = √3 , evaluate.
(i) 4 sin3 x - 3 sin x.
(ii) 3 cos x - 4 cos3 x.​

Answers

Answered by pal69
2

Step-by-step explanation:

2sinx=√3

sinx=√3/2

x=60°.

1).

4sin3x-3sinx=4sin180°-3sin60°

= 4*0-3*√3/2

=-3√3/2

2)

3cosx-4co3x=3*cos60°-4cos180°

=3*1/2 -4*(-1)

=3/2 +4=11/2

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