Question

24. If 2 sin x = √3. evaluate.
(i) 4 sin³x - 3 sinx
(ii) 3 COS x- 4 cos³x​

Answer 1

we know that

(i) 4 sin³x - 3 sinx= sin3x

(ii) 3 COS x- 4 cos³x= cos3x

$\sin(x) = \frac{ \sqrt{3} }{2} \\ = > x = \frac{\pi}{3}$

$= > \sin(3 .\frac{\pi}{3} ) = \sin(\pi) = 0 \\ = > \cos(3 .\frac{\pi}{3} ) = \cos(\pi) = - 1$

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