Math, asked by papakipari835, 2 months ago


24. If 4m +8,2m2 +3m +6,3m2 + 4m + 4 are three consecutive terms of an A.P. find m.​

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Answered by MoniReddy
2

ANSWER▶️

  • First term = 4m+8

  • First term = 4m+8Second term = 2m2+3m+6

Answer:

First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first term

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So,

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2

Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2 Step-by-step explanation:

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