24. If 4m +8,2m2 +3m +6,3m2 + 4m + 4 are three consecutive terms of an A.P. find m.
Answers
ANSWER▶️
- First term = 4m+8
- First term = 4m+8Second term = 2m2+3m+6
Answer:
First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first term
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So,
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2
Answer:First term = 4m+8Second term = 2m2+3m+6Third term = 3m2+4m+4Common Difference d = second term - first termd = (2m2+3m+6)−(4m+8)d = 2m2−m−2Common Difference = third term - second term d = (3m2+4m+4)−(2m2+3m+6)d = m2+m−2So, 2m2−m−2=m2+m−2m2−2m=0m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2 Step-by-step explanation: