24. If 8 tan A = 15, find sin A -cos A.
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In a right angled triangleBC=15, AB=8
Then according to Pythagorean theorem Ac^2=AB^2+BC^2
AC=sqrt(64+225)
AC=17
sin A=15/17
cos A=8/17
sin A_cos A= 7/17
Then according to Pythagorean theorem Ac^2=AB^2+BC^2
AC=sqrt(64+225)
AC=17
sin A=15/17
cos A=8/17
sin A_cos A= 7/17
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