Question

24. If sin (A+B)= ✓3/2andcos(A-B)=✓3/2,0°<(A+B)≤90°andA>B then find the values of A and B.
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Answer 1

Answer:

We have :

sin(A+B) = SQ.ROOT 3/2 = sin60

Therefore, A+B =60

Now taking ,

cos(A-B) = sq.root 3/2 = cos30

A-B=30

Therefore, from above two equations we get A = 45degree and B = 15degree.