Question

24. If the distance travelled by a body in the nth
second is given by (4 + 6n) m, then find the
initial velocity and acceleration of the body
respectively.
(NTSE 2012​

Answer 1

Answer: This may help you

Explanation:

s

nth

​

=u+

2

a

​

(2n−1)

4+6n=u+

2

a

​

(2n−1)

=(u−

2

a

​

)+an

a=6m/s

2

u−

2

a

​

=4

u−3=4

u=7m/s