Question

24.
In Fig. the sides AB and AC of AABC are produced to points 'E' and 'D' respectively. If bisectors
BO and CO of ZCBE and BCD respectively meet at point O, then prove that

ZBOC = 90° - - ZBAC.
2​

Answer 1

Refer The Attachment ⬆️

$\green{\bf{@MrMonarque}}$

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