24. In the figure find the value of Sin C + Cos A ?
13
5
Te
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AC
2
=100−36
AC
2
=64
AC
2
=8
2
AC= 8
(i) sin B = perpendicular/ hypotenuse
= AC/BC
= 8/10
= 4/5
(ii) cos C = Base/hypotenuse
= AC/BC
= 8/10
= 4/5
(iii) sin B = Perpendicular/hypotenuse
= AC/BC
= 8/10
= 4/5
Sin C = perpendicular/hypotenuse
= AB/BC
= 6/10
= 3/5
Now,
Sin B + sin C = (4/5) + (3/5)
= (4 + 3)/5
= 7/5
(iv) sin B = 4/5
Cos C = 4/5
Sin C = perpendicular/ hypotenuse
= AB/BC
= 6/10
= 3/5
Cos B = Base/Hypotenuse
= AB/BC
= 6/10
= 3/5
sin B cos C +
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