Question

24. In the given figure, ∆ABE and ∆CDE are right angled triangles. Find the length AC.
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Answer 1

Answer:

15

Step-by-step explanation:

In∆ABE,

Right angled∆,

by Pythagoras theorem

BE^2=AB^2+AE^2

25=16+AE^2

3=AE

In ∆CDE,

Right angled∆,

by Pythagoras theorem

DE^2=CE^2+CD^2

12=CE

C-E-A

CA=CE+AE

=12+3

=15

Answer 2

Answer:

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