Math, asked by anmolkatara63, 4 months ago

24. In the given figure, PQ is a tangent to the
circle at A. AB and AD are bisectors of
ZCAQ and ZPAC. If ZBAQ = 30°, prove
that : BD is diameter of the circle.
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Answers

Answered by yamunadolugmailcom
0

Answer:

you answer check Google

(())xxyy { { { { \frac{ \frac{ \sqrt{ \sqrt{ \sqrt[ \sqrt[ \sqrt[ | | <  <  >  >  \leqslant  \leqslant  \geqslant  \geqslant | | ]{?} ]{?} ]{?} } }  \times \frac{?}{?}  \times \frac{?}{?} }{?} }{?} }^{?} }^{?} }^{2} }^{2}

you can get the answer to check Google

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