Question

24.
In the reaction X + Y →XY, if
the concentration of X and Y are
doubled, the rate of reaction will
increase :-
(A) 2 times
(B) 4 times
(C) Half
(D) One Fourth​

Answer 1

Answer:

2 times will be rate of reaction

Answer 2

Given info : In the reaction, X + Y ⇒ XY, if the concentration of X and Y are doubled.

To find : the rate of reaction will increase ...

solution : given chemical reaction is ..

             X    +    Y   ⇒   XY

let reaction constant is k and initial concentration of X is [|X] and initial  concentration of Y is [Y].

∴ the rate of reaction, R = k[X]¹[Y]¹ = k[X][Y]   ...(1)

now the concentration of X and Y are doubled,

i.e., concentration of X = 2[X]

concentration of Y = 2[Y]

so the rate of reaction, R' = k(2[X])(2[Y]) = 4k[X][Y]  ...(2)

from equations (1) and (2) we get,

R/R' = 1/4 ⇒ R' = 4R

therefore the rate of reaction will increase 4 times of its initial rate of reaction.