Question

24 J work is done in moving a charge of 6 C between two points calculate the p.d between these two points​

Answer 1

Solution :

⏭ Given:

✏ Work done to move a charge = 24J

✏ Charge on particle = 6C

⏭ To Find:

✏ P.d. between two points

⏭ Formula:

✏ Relation between charge, potential difference and work done is given by

• W = q × ΔV

⏭ Terms indication:

• W denotes work done
• q denotes charge on particle
• ΔV denotes p.d.

⏭ Calculation:

✏ 24 = 6 × ΔV

✏ ΔV = 24/6

✏ ΔV = 4 Volt

___________________________

➡ Potential difference between two points = 4 Volt.

Answer 2

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

Work done (w) = 24 J

Charge (q) = 6 C

We know that , the work done (w) to move a unit charge (q) from infinity to a particular point is called potential difference (v)

$\large \mathtt{\fbox{Potential \: difference = \frac{w}{q} } }$

Thus ,

Potential difference = 24/6

Potential difference = 4 volt

Hence , the potential difference is 4 volt

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