Question

24. किसी कार्यालय में कर्मचारियों का औसत वेतन 1800 रु. है। पाँच कर्मचारियों की नियुक्ति
के बाद कुल वेतन 4000 रु० बढ़ गया तथा औसत वेतन 200 रु. घट गया। कर्मचारियों
की वर्तमान संख्या बताएँ।​

Answer 1

Answer:

In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC)A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC)A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC)A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC)A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

11. In the given figure, medians AD and BE of AABC meet at G

and DF | BE.

Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

(Hint. angleEBC - angleFDC)