Question

24. Let R1 and R2 are remainders when polynomials f(x) = 4x3+3x2-12ax-5 and
g(x)=2x3+ax2- 6x -2 are divided by (x-1) and (x-2) respectively. If 3R1 + R2 =28.
Find a​

Answer 1

Answer:

given,3R1 + R2 =28.

3(12a+2)+4a+2=28

36a+6+4a+2=28

40a+8=28

40a=28-8

a=20/40

a=1/2

rachana**

Answer 2

Ur answer is a/2 is equal to 6.

Hope it helps uhh