24 men can complete a piece of work in 18 days while 12 women can complete the same piece of work in 28 days. 27 men start working and are replaced by 14 women after 8 days. In how many days will 14 women finish the remaining work?
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24 men complete 1 work in 18 days.
What part of work Will 27 men do in 8 days ?
M1D1W1M1D1W1 = M2D2W2M2D2W2
=> 24×18124×181 = 27×8W227×8W2
W2W2 = 27×824×1827×824×18 = 1212
Remaining work = 1−121−12 = 1212
This part of work is to be done by 14 women.
∴M1D1W1∴M1D1W1 = M2D2W2M2D2W2
=> 12×28112×281 = 14×D21214×D212
=> 14×D214×D2 = 12×12×2812×12×28
=> D2D2 = 6×28146×2814 = 12 days
24 men complete 1 work in 18 days.
What part of work Will 27 men do in 8 days ?
M1D1W1M1D1W1 = M2D2W2M2D2W2
=> 24×18124×181 = 27×8W227×8W2
W2W2 = 27×824×1827×824×18 = 1212
Remaining work = 1−121−12 = 1212
This part of work is to be done by 14 women.
∴M1D1W1∴M1D1W1 = M2D2W2M2D2W2
=> 12×28112×281 = 14×D21214×D212
=> 14×D214×D2 = 12×12×2812×12×28
=> D2D2 = 6×28146×2814 = 12 days
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