Question

24 men working 8 h a day can finish a work in 10 days. working at a rate of 10 h a day, the number of men required to finish the work in 6 days is

Answer 1

24 men, 8 hr, 10 days
? 10 hr, 6 days
=10×6/24×8×10
=1/32 men

Answer 2

Answer:

$\red { Number \: men \: required \: to}$

$\red { finish \: the \: work }$

$\green { = 32 }$

Step-by-step explanation:

$Here, we \:have \: three \: quantities \: i.e \\number \: of \: men ,\: number \: of \: hours\\per \: day \: and \: number \: of \: days$

$number \: of \: men (x_{1} ) = 24,$

$number \: of \: hours \: per \:day (h_{1}) = 8$

$Number \: of \: days (d_{1}) = 10$

$number \: of \: men (x_{2} ) = \red{?}$

$number \: of \: hours \: per \:day (h_{2}) = 10$

$Number \: of \: days (d_{2}) = 6$

$m_{2}\times h_{2}\times d_{2} =m_{1}\times h_{1}\times d_{1}$

$\implies m_{2}\times 10\times 6 =24 \times 8\times 10$

$\implies m_{2} = \frac{24\times 8 \times 10}{10\times 6 }\\= 32$

Therefore.,

$\red { Number \: men \: required \: to}$

$\red { finish \: the \: work }$

$\green { = 32 }$

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