Question

24 squares of side length 1 cm are joined (edge to edge) to form a rectangle. What can be the least and the greatest perimeter of the rectangle formed?​

Answer 1

Given data :-

◐ Twenty four squares of side length 1 cm are joined (edge to edge) to form a rectangle.

Solution :-

◐ If twenty four squares are joined edge to edge in a linear way, then it form's a rectangle of length 24 cm and breadth 1 cm.

Now, by formula of perimeter of rectangle

◐ Length = L & Breadth = B

→ Perimeter of rectangle = 2 ( L + B )

→ Perimeter of rectangle = 2 ( 24 + 1 )

→ Perimeter of rectangle = 2 × 25

→ Perimeter of rectangle = 50 cm

Hence, the least and the greatest perimeter of the rectangle formed is 50 cm.

Answer 2

Answer:

Least perimeter =20 cm

Greatest perimeter =50 cm

Step-by-step explanation:

There are four possible arrangements:

Step : 1 of 4

There are four possible arrangements:

Perimeter =2(l+b)=2(6+4)=20 cm

Please refer first attachment for the image

Step : 2 of 4

Perimeter =2(l+b)=2(8+3)=22 cm

Please refer second attachment for the image

Step : 3 of 4

Perimeter =2(l+b)=2(12+2)=28 cm

Please refer third attachment for the image

Step : 4 of 4

Perimeter =2(l+b)=2(24+1)=50 cm

Please refer fourth attachment for the image

Hence,

Least perimeter =20 cm

Greatest perimeter =50 cm