24. The coefficient of concurrent deviation for p pairs of observations was found to be
number of concurrent deviations was found to be 6, then the value of p is
(a) 10
(b)9
(c) 8
(d)none of these
Answers
Answered by
67
Step-by-step explanation:
Given 24. The coefficient of concurrent deviation for p pairs of observations was found to be 1/√3 number of concurrent deviations was found to be 6 then the value of p is
(a) 10
(b)9
(c) 8
(d)none of these
- Given coefficient of concurrent deviation is given by R = ±√2 c – m / m
- Now m = p – 1 and c = 6 and R = 1/ √3
- So 1/√3 = √2 x 6 – (p – 1) / p -1
- 1/√3 = √12 – p + 1 / p – 1
- Squaring both sides we get
- 1/3 = 13 – p / p – 1
- Or p – 1 = 39 – 3p
- 4p = 40
- Or p = 40 / 4
- Or p = 10 pairs
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Answered by
7
Answer:
10
Step-by-step explanation:
Given:
r = 1/√3
c = 6
r = +-√(2c - m)/m
1/√3 = √(2*6 - m)/m
Squaring on both sides
1/3 = (12 - m)/m
m = 36 - 3m
4m = 36
m = 9
p = 9 + 1
p = 10
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