Science, asked by ms2255710, 1 month ago

24 The decomposition of NH3 on
platinum surface
surface is zero order
reaction what
of production of N₂ and H₂
respectively if k= 2.5 x 104 molt
the
rates
LS-1
a.) 2.5x104 mol st and 7.5 x 10-4
mal sol
b. 5.5x10 malls and 7.50109
moll-IS-
C) 7.5x 10 moll-st and 2.58 104
malls-
d.) 8.5x15 4 molt 51 and 7.5 x 104
-1
:-)​

Answers

Answered by Utalk71
0

Answer:

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Answered by roshnigeorge38
0

Answer:

2NH3(g) → N2(g) + 3H2(g)

Rate of zero order reaction is equal to rate constant. i.e. Rate = 2.5 × 10-4mol L-1sec-1.

According to rate law,

2.5 × 10-4mol L-1sec-1 =

i.e. the rate of production of N2 is 2.5 × 10-4mol L-1 sec-1.

According to rate law,

( Refer to img attached above)

i.e. rate of formation of H2 is 3 times rate of reaction = 3 × 2.5 × 10-4mol L-1sec-1

= 7.5 × 10-4mol L-1sec-1

Option (c)

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