Question

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24: The diagonals of a parallelogram PQRS intersect at 0. If angle QOR= 8O*and angle PRO
30" then, find angle OSP​

Answer 1

Answer:

SOR=180

∘

−∠QOR=90

∘

(Since angles forming a linear pair are complementary)

Consider ΔSOR,

∠SOR+∠OSR+∠ORS=180

∘

(angle sum property of triangles)

∴∠ORS=180

∘

−90

∘

−50

∘

=40

∘

solution