24. The expression x2 + kx + 9 becomes positive for what values of k (given that x is real)?
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0
Answer:
The values of k for which the given quadratic equation has real and distinct roots x^2 - kx + 9 = 0 is k 6 .
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4
Answer:
when d < 0 and a > 0, the quadratic expression becomes positive for any real x value.
ax^2 + bx + c:
discriminant: d = b^2 - 4ac
d = k^2 - 4(1)9 < 0
k^2 < 36
-6 < k < 6
Since a = 1 > 0, the expression becomes positive when k ∈ (-6, 6)
Step-by-step explanation:
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