Math, asked by ankita1123, 1 year ago

24. The factors of
(x^2 + 2x)^2 - 3(x^2 + 2x) - y(x^2 + 2x) + 3y are
(a) (x - 1)(x + 3)(x^2 + 2x + y)
(b) (x - 1) (x + 3) (x^2 + x - y)
(C) (x - 1) (x - 3)(x^2 + 2x - y).
(d) None of the above

Answers

Answered by preeth3
3

thank you mark me as brainliest

Attachments:
Answered by KingSrikar
2

\rm{\left(x^2+2x\right)^2-3\left(x^2+2x\right)-y\left(x^2+2x\right)+3y}

\rm{=\left(x^2+2x\right)\left(x-1\right)\left(x+3\right)-y\left(x-1\right)\left(x+3\right)}

\rm{=\left(-1+x\right)\left(3+x\right)\left(x^2+2x\right)-\left(-1+x\right)\left(3+x\right)y}

\rm{=\left(-1+x\right)\left(3+x\right)\left(x^2+2x-y\right)}

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