24.The following observations have been arranged in ascending order. If the median of the data is 63, find x: 29, 32, 48, 50, x, x+2, 72, 78, 84, 95.
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37
The given data is arranged in ascending order as
29,32,48,50,x,x+2,72,78,84,95.
The total number of observations n = 10(Even).
Therefore the median of the data will be mean of 10/2 i.e 5th and 10/2 + 1 = 6th observation.
Given Median = 63.
(x + x + 2)/2 = 63
x + x + 2 = 63 * 2
x + x + 2 = 126
x + x = 126 - 2
x + x = 124
2x = 124
x = 124/2
x = 62.
Therefore the value of x = 62.
Hope this helps!
29,32,48,50,x,x+2,72,78,84,95.
The total number of observations n = 10(Even).
Therefore the median of the data will be mean of 10/2 i.e 5th and 10/2 + 1 = 6th observation.
Given Median = 63.
(x + x + 2)/2 = 63
x + x + 2 = 63 * 2
x + x + 2 = 126
x + x = 126 - 2
x + x = 124
2x = 124
x = 124/2
x = 62.
Therefore the value of x = 62.
Hope this helps!
siddhartharao77:
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Answered by
15
median=(n÷2)th +(n÷2+l)thwhole divide 2
63=5th+6th whole divide by 2
63=x+x+2whole divide by 2
63 =2x+2divided by 2
63×2=2x+2
126-2=2x
124divide by 2=x
62=x
63=5th+6th whole divide by 2
63=x+x+2whole divide by 2
63 =2x+2divided by 2
63×2=2x+2
126-2=2x
124divide by 2=x
62=x
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