Question

24
The length of a rectangle is (4x-
3y)cm and its breadth is (2x+y)cm.
Calculate is
i. Perimeter
ii. Area
iii. Actual perimeter and its area if
x = 3 cm and y = 2 cm.
(Non-anonymous question, ) (4​

Answer 1

Answer:

i.perimeter=2(6x-2y)cm

ii.area=8x^2 - 2xy - 3y^2 cm^2

iii.actual perimeter= 28 cm

actual area=48 cm^2

Step-by-step explanation:

i.perimeter=2(l+b)

=2(4x-3y +2x +y)cm

=2(6x-2y)cm

ii.area=(4x-3y)(2x+y)

=8x^2 +4xy -6xy -3y^2

=8x^2 - 2xy -3y^2 cm^2

iii.actual perimeter=2(18 - 4) cm

=28 cm

actual area=72-12-12

=48 cm^2

[by putting values of x and y in (i) and (ii)]

thank you

Answer 2

Step-by-step explanation:

I hope it helps you

perimeter=12x-4 y

Area=8x²-2xy-3y²

Actual perimeter=28cm

Actual area=48cm²