24. The minimum horizontal force applied to the
centre of wheel of radius R and weight w to pull
R
it over a step of height R/2
F
R/2
W
(1) W
(2)
2
w
(3) w/3
(4)
Attachments:
Answers
Answered by
3
Answer:
(3) w√3
Explanation:
Here, we use pythagorus theorem and angular equating law.
Hint:- angular torque = horizontal force or ang.torq.>hz.force unless the wheel not stepup..
Hope u get it...
Attachments:
Answered by
0
the answer is W√3 hope it helps you
Similar questions