Math, asked by purohitprerna8, 5 months ago

24. The polynomials ax3 + 3x2 - 13 and 2x3 - 5x + a, when divided by (x - 2) leave same remainder. Find the value
of a.

Answers

Answered by sangeetadevi1140

0

Answer:

Answer is = ax2

Step-by-step explanation:

Q. ax3+3x2-13 and 2x3-5x+a ÷ (x-2)

= ax3+6-13+6-9+5x÷(x-2)

= ax3+6-7-9+5x÷(x-2)

= ax3+6-16+5x÷(x-2)

= ax3-10+5x÷(x-2)

= ax3-5x÷(x-2)

=ax2x÷(x-2)

=ax2x-x

=ax2

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