Question

24.
Two numbers are in the ratio 2:3. If their L.C.M. is 48. What is sum of the numbers?
a. 28
b. 40
C.64
d 42
e None of these​

Answer 1

Step-by-step explanation:

L.C.M =48 ,

H.C.F= axb/L.C.M=3x2/48=1/8 ,

Then , 6x=48 , x=8

2x+3x= 2(8)+3(8)= 16+24 =40

So , the sum of two numbers is 40.

I think so