24 volt battery is connected across the unknown resistor there is a current of hundred m a in the
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V=12v I=2.5mA=2.5×10^-3 ×10 = 25× 10^-4R= ?R=V/I R=12/25× 10^-4R=12×10^4/25R=12 × 10000/25R =4800 Therefore, R = 4800 ohms.
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