Question

24. What is the chance of throwing a sum greater than or equal to 7 in a throw of 2 dice? a. 7/12
b. 1/3
c. 3/4
d. 13/36

Answer 1

Answer:

a. 7/12

Step-by-step explanation:

total outcomes = 36

possible outcomes are:-

(1,1)    (2,1)   (3,1)   (4,1)   (5,1)   (6,1)

(1,2)   (2,2)  (3,2)  (4,2)  (5,2)  (6,2)

(1,3)   (2,3)  (3,3)  (4,3)  (5,3)   (6,3)

(1,4)   (2,4)  (3,4)  (4,4)  (5,4)   (6,4)

(1,5)   (2,5)  (3,5)  (4,5)  (5,5)  (6,5)

(1,6)   (2,6)  (3,6)  (4,6)  (5,6)  (6,6)

Favourable outcomes ( sum greater or equal to 7) = 21

P(to get sum equal or greater than 7)= 21/36  = 7/12

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