Math, asked by parimalmandal793, 2 months ago

24. What is the probability when an ordinary year has 53 sundays?

Answers

Answered by yamin1971mya

0

Answer:

1/7

Step-by-step explanation:

Non-leap year = 365 days

In 365 days, Number of weeks = 52 weeks and 1 day is remaining.

For 52 weeks number of Sundays = 52

1 remaining day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.

Total of 7 outcomes, the favourable outcome is 1.

∴ probability of getting 53 Sundays = 1 / 7.

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