Question

24) What is the solution of the
equation 8x+3y=5 and 3x-
2y=5=?​

Answer 1

Answer:

x = 1, y = -1

Explanation:s

Assume that 8x+3y=5 as equation 1

3x-

2y=5 as equation 2

Now multiply equation 1 with 2 and equation 2 with 3

     16x+6y=10

      9x-6y=15

     25x     = 25           (both 6y and -6y are cancelled)

so, x = 25/25 = 1

  ⇒ x = 1

Now substitute the x value in equation 1

8(1)+3y=5

8+3y=5

3y=5-8

3y= -3

y= -3/3

⇒y = -1

Hope it helps you.

Answer 2

Answer:

(1,-1) should be the answer

Explanation:

8x + 3y=5 (1st equation)

3x -2y =5 (2nd equation)

multiply 1st equation with 2 and 2nd equation with 3

you will get

16x + 6y = 10

9x - 6y = 15

(Add both the equations)

16x + 6y = 10

9x - 6y = 15

25x = 25 (because +6 and -6 gets cancel)

x = 1

Now put value of x in 2nd equation

3x -2y =5

3×1 -2y=5 (putting the value of x)

3-2y=5

-2y=5-3

-2y=2

y = -1

therefore x=1 and y= -1

hope you like it