Question

24. What volume of M/6 H3PO4 soln will
completely react with 200ml of soln of M/2
aluminium carbonate?
a.1200ml
b. 800 ml
c. 400 ml
d. 300 ml​

Answer 1

Answer:

A) 1200ml

Explanation:

Molarity of H3PO4 = $\frac{1}{6}$ Molar

n- factor of H3PO4= 3                                             (3H+)

Let the Volume of H3PO4 be Vml.

Molarity of Al2(CO3)3 = $\frac{1}{2}$ Molar

n-factor of Al2(CO3)3= 6                                         (2Al3+)

Volume of Al2(CO3)3 = 200ml or $\frac{200}{1000}$ L

Acc to law of equivalence:-

Equivalent of H3PO4 used= Equivalent of Al2(CO3)3 used

(∴ Equivalent = Molarity x n-factor x V in L)

$\frac{1}{6}$ × 3 ×$\frac{Vml}{1000}$   =  $\frac{1}{2}$ × 6 × $\frac{200}{1000}$

∴Vml= 1200 ml (A)