Question

24. What would happen to the volume of a balloon filled with 0.357L of
H2 gas collected at 741.3 mm Hg if the atmospheric pressure increased
to 758.1 mm Hg?​

Answer 1

Answer:

The volume of a balloon with H₂ gas decreases by 8mL when atmospheric pressure changes from 741.3 mmHg to 758.1 mmHg.

Explanation:

Given,

    Initial volume, V₁ = 0.357L

  Initial Pressure, P₁ = 741.3 mmHg

  Final Pressure, P₂ = 758.1 mmHg

We have to find the volume of the balloon, V₂ at 758.1 mmHg,

Boyle's Law gives the relation,

                  P₁V₁ = P₂V₂

Rearranging the equation,

                      V₂ = P₁V₁ /  P₂

Substituting the values of P₁, V₁, and P₂

                     V₂ = 741.3×0.357 / 758.1 = 0.349L

              V₁ - V₂ = 0.357L - 0.349L = 8mL

Hence, the volume decreases by 8mL