Question

240 beads are distributed among a, b and c in the ratio 2:3:5 how many more beads did c receive than that of a?
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Answer 1

Step-by-step explanation:

Total = 240

and no. of beads given to a,b and c are in the ratio 2:3:5 ,

so let us take the common ratio as x ,

then a = 2x

b = 3x

c = 5x

ATQ,

a + b + c = 240

putting the values of a,b and c ,

2x + 3x + 5x = 240

10x = 240

x = 240 / 10

x = 24

so,

c = 5x

c = 5 X 24

c = 120

and,

a = 2x

a = 2 X 24

a = 48

ATQ,

c - a = 120 - 48

= 72

=> c has 72 more beads than a

Answer 2

ANSWER: 72

Step-by-step explanation:

their are total 240 beads

a=2x b=3x c=5x

a+b+c=240

2x+3x+5x=240

10x=240

x=240÷10

x=24

a=2×24=48

b=3×24=72

c=5×24=120

c-a=120-48=72